If it's not what You are looking for type in the equation solver your own equation and let us solve it.
0.9x^2+3x-5=0
a = 0.9; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·0.9·(-5)
Δ = 27
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{27}=\sqrt{9*3}=\sqrt{9}*\sqrt{3}=3\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{3}}{2*0.9}=\frac{-3-3\sqrt{3}}{1.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{3}}{2*0.9}=\frac{-3+3\sqrt{3}}{1.8} $
| 3v^2+54v−93=0 | | 3v2+54v−93=0 | | -2/3v=-8 | | 3a+10=−38 | | n−12=−9 | | x−0.17x=2 | | X+9y=6y-7 | | 2√x=4√3 | | x−0.1x=10 | | 75=2g-7 | | 42=-6(-2a2+11) | | 7=4/w+7 | | (5/12)x=1 | | (5+12)x=1 | | 3×(x+2)=12 | | 48w+78=0 | | 3^(2x)+3^(x)-2=0 | | 8w+11=3 | | 7y-2(5+3y/2)=5y-17y= | | x=(7/2-5/2)/(3+5/3) | | -1/2b=21b= | | 2y+29-8y=5y= | | 3(x/5-4/3)=7(x–1/3) | | 0.60+x-0.60x=0.94 | | 180-30+x=180 | | 6x=6-x | | 180-8=5x | | x=180-5x+8 | | 11^x=78 | | 3(2x+2)+4(x+5)=56 | | 20x-7x=6x+6 | | 3x+2=1/2x-5 |